(continued)....The sphere is fixed to a platform and doesn\'t move. The penny sl
ID: 2093035 • Letter: #
Question
(continued)....The sphere is fixed to a platform and doesn't move. The penny slides down from rest and leaves the sphere at a certain point. How far will the penny fall away from the point of contact of the sphere and the platform?
So I was thinking to find the velocity at release by using N=0 and mgh=1/2 m v^2. And you can find h using the angle. Once you know v, you are in business. V will be pointing down and tilted away from the sphere. You project that v on the horizontal line and look for x, but you need the time. You can get the time from the height, using kinematics, but don
Explanation / Answer
Find the velocity where centripetal acceleration matches gravitational acceleration
g = v
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