(c24p56) Consider two widely separated conducting spheres, 1 and 2, the second h

Question

(c24p56) Consider two widely separated conducting spheres, 1 and 2, the second having twice the diameter of the first. The smaller sphere initially has a positive charge q . 6.00x10-6 . and the larger one is initially uncharged. You now connect the spheres with a long thin wire. How are the final potentials V1 and V2 of the spheres related? Find the final charges q1 and q2. q1? Submit Answor Incorrect. Tries 1/99 Previous Tries 92? Submit Answor Incorrect. Tries 1/99 Previous Tries What is the ratio of the final surface charge density of sphere 1 to that of sphere 2? Submit Answer Incorrect. Tries 1/99 Previous Tries

Explanation / Answer

final potential, V1 = V2

k q1 / (r) = k q2 / (2r)

q2 = 2 q1

Applying charge conservation

q1i + q2i = q1 + q2   

(6 x 10^-6) + 0 = q1 + 2q1

q1 = 2 x 10^-6 Or 2 uC .....Ans

q2 = 2q1 = 4 x 10^-6 C OR 4 uC .....Ans

surface charge density = q / (4 pi r^2)

ratio = (q1 /q2)(r2/r1)^2

= (2/4)(2r/r)^2

= 2

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