TTOP Mation and between rocedures that your specific computer program has to dec
ID: 2933002 • Letter: T
Question
TTOP Mation and between rocedures that your specific computer program has to decide if this variable is approx- any of newb mial tes newbor nonsmo imately normally distributed. According to the National Center for Health Statistics, as of 2012, it is estimated that 24% of adults in Missouri smoke. You wish to know the probability of selecting from this popula- Died in Alive at tion a random sample of 30 people containing 8 8.14 The fol betwee binomi mine it more li who do or fewer smokers. a. Use a statistical program to determine the exact probability of getting 8 or fewer smok- ers. (Hint: refer to section 5.4.) b. Now use the normal approximation of the binomial distribution to answer the same question. Compare your answers. Are they Heart No Hea similar? 8.10 A population of red-bellied snakes is known to have a ratio of grey color morph to red color morph of 53:47. You wish to know the probabil- ity of selecting a random sample of 20 snakes Notes The probabili containing 3 or fewer red morph individuals. a. Use a statistical program to determine the exact probability of getting 3 or fewer greyWe cannot th ity (or freque fore, a line d Thus, there i morph individuals. b. Now use the normal approximation of the binomial distribution to answer the same However, i together, we the curve th may assign question. Compare your answers. Are they similar? 8.11 The Northern Leopard Frog, which is easilyay te common throughout the United States and nedecor an times çalled its body, is 2 For a detail 3 This particul distinguished by spots covering Loonard frogExplanation / Answer
Q.8
(a) N = 30 and p = 0.24 (Proportion of people who smoke )
Pr(X <= 8 ; 30 ; 0.24) From statistical program or Excel = 0.7193
(b) Here N = 30 and p = 0.24
by using normal approximation = 30 * 0.24 = 7.2
= sqrt [30 * 0.24 * 0.76] = 2.34
Pr(X <= 8 ; 7.2 ; 2.34) = Pr(X < 8.5 ; 7.2; 2.34) [By using Continuity Correction factor]
Z = (8.5 - 7.2)/2.34 = 0.56
by Z - table
Pr(X <= 8 ; 7.2 ; 2.34) = 0.7123
Yes , we get similar answers when we compare them.
Question 8.10
Pr(Grey Color Morph) = 0.53
Pr(Red Color Morph) = 0.47
Pr(X <= 3 grey color morph ; 20; 0.53) by excel = 0.000526
(b) Here N = 20 and p = 0.57
by using normal approximation = 20 * 0.53 = 10.6
= sqrt [20 * 0.53 * 0.47] = 2.232
Pr(X <= 3) = NORM(X < 3.5 ; 10.6 ; 2.232)
Z = (3.5 - 10.6)/ 2.232 = -3.18
Pr(Z = -3.18) = 0.000736
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