1. The 2009-2010 National Health and Nutrition Examination Survey, estimated pop

Question

1. The 2009-2010 National Health and Nutrition Examination Survey, estimated population parameters for men over the age of 40, and came up with an average dBP of 66 mmHg, and standard deviation of 15 mmHg.   The dBP values were normally distributed.   A dBP of less than 60 mmHg is generally considered hypotensive (low BP), if clinical symptoms are also present (poor circulation, light headed, etc). A diastolic blood pressure between 80 and 99 mmHg is described as prehypertension(high blood pressure), and is treatable with lifestyle changes, rather than medication, and a dBP higher than 99 is considered hypertension and is often treated with medication.

What percentage of NHANES subjects are normotensive (neither low dBP, nor high dBP)?

2. The measurement of heart rate variability reveals information on the functional state of the autonomic nervous system. In healthy neonates, population-based studies have shown the average heart rate of healthy neonates is 122 beats per minute (BPM) with a standard deviation of 12. A clinical sample of 30 infants with respiratory distress syndrome is found to have an average BPM of 140. The probability that chance alone led to such a high sample mean is very low. True or false?

3. The measurement of heart rate variability reveals information on the functional state of the autonomic nervous system. In healthy neonates, population-based studies have shown the average heart rate of healthy neonates is 122 beats per minute (BPM) with a standard deviation of 12. A clinical sample of 30 infants with respiratory distress syndrome is found to have an average BPM of 140. The probability that chance alone led to such a high sample mean is very low.

4. Given the average weight of 6th graders is 80 lbs with standard deviation of 20 lbs, what is the probability that the mean weight of a sample of 50 of these students will be less than 75 lbs?

Explanation / Answer

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4) Mean = 80

SD = 20

z = (75 - 80)/20/50

z = - 1.77

P( z < - 1.77) = 0.0384

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