need help on #8,9,10,11 that a sample is used to estimate a population proportio
ID: 2930409 • Letter: N
Question
need help on #8,9,10,11
that a sample is used to estimate a population proportion p. Find the margin of error M.E. that corresponds to a sample of size 321 with 151 successes at a confidence level of 90%. Answer should be obtained without any preliminary rounding, However, the critical value may be rounded to 3 decimal places. #8 Points possible: 1 . Total attempts: 1 Assume that a sample is used to estimate a population proportion p. Find the 99% confidence interval for a sample of size 341 with 33.1% successes. Enter your answer as an decimal places. 99% C.1. Answer should be obtained without any preli (i.e., use parentheses) using decimals (not percents) accurate to three may be rounded to 3 decimal placesExplanation / Answer
Ans:
8) z value for 99% CI is 2.58
99% CI
=0.331+/-2.58*sqrt(0.331*(1-0.331)/341)
= 0.331+/-2.58*0.0255
=0.331+/-0.066
=(0.265, 0.397)
9)sample proportion=42/146=0.288
z value for 99.9% CI is 3.291
99.9% CI
=0.288+/-3.291*sqrt(0.288*(1-0.288)/146)
=0.288+/-3.291*0.0375
=0.288+/-0.123
=(0.165,0.411)
10)z value for 80% CI is 1.28
80% CI
=0.481+/-1.28*sqrt(0.481*(1-0.481)/235)
=0.481+/-0.033
=(0.448,0.514)
11)z value for 99.5% CI is 2.807
Required sample size,n=2.8072*0.13*(1-0.13)/0.0152
n=3961
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