SE 50B XP My Notes Ask Your Teacher What do you think is the ideal number of chi
ID: 2927644 • Letter: S
Question
SE 50B XP My Notes Ask Your Teacher What do you think is the ideal number of children for a family to have?" A Gallup Poll asked this question of 1016 randomily chosen adults. Almost half (49%) thought two children was ideal, t we are supposing that the proportion of all adults who think that two children is ideal is p 0.49 what is the probability that a sample proportion falls between 0.46 and 0.52 (that is, within ±3 percentage points of the true p) if the sample is an SRS of size n . 350? (Round your answer to four decimal places.) what is the probability that a sample proportion jp fails between 0.46 and 0.52 if the sample is an SRS of size n- 5000? (Round your answer to four decimal places.) Combine these results to make a general statement about the effect of larger samples in a sample survey O Larger samples give a smaller probability that p will be close to the true proportion p. Larger samples have no effect on the probability that p will be dose to the true proportion p. OLarger samples give a larger probabity that p will be close to the true proportion p. -n points MirtroSa 5E510.XP My Notes Ask Your TeadExplanation / Answer
Given, p = 0.49 and n = 350
Standard error of the proportion = sqrt(p(1-p)/n) = sqrt(0.49(1-0.49)/350) = 0.0267
Z value for p = 0.46 is (0.46 - 0.49)/ 0.0267 = -1.12
Z value for p = 0.52 is (0.52 - 0.49)/ 0.0267 = 1.12
P(0.46 < p < 0.52) = P(-1.12 < Z < 1.12) = P(Z < 1.12) - P(Z < -1.12)
= 0.8686 - 0.1314 = 0.7372
Now, n = 5000
Standard error of the proportion = sqrt(p(1-p)/n) = sqrt(0.49(1-0.49)/5000) = 0.007
Z value for p = 0.46 is (0.46 - 0.49)/ 0.007 = -4.28
Z value for p = 0.52 is (0.52 - 0.49)/ 0.007 = 4.28
P(0.46 < p < 0.52) = P(-4.28 < Z < 4.28) = P(Z < 4.28) - P(Z < -4.28)
= 0.9999 - 0 = 0.9999 (or 1)
So, the correct option is,
Large samples give larger probability that p^ will be close to the true proportion p
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