I need help with part e) I don\'t know how to explain 2 The local lottery is fou
ID: 2927539 • Letter: I
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I need help with part e) I don't know how to explain
2 The local lottery is found by randomly selecting 6 ping-pong balls from a container in order without replacement. There are 30 ping-pong balls in the container numbered 0 through 29. a) What is the probability you hold the winning ticket? b) How many tickets should you buy to give yourself a 1% chance of winning the lottery? A 10% chance? A 25% chance? A 50% chance? c) What is the probability all 6 numbers are even? At least one number is odd? d) What is the probability each number will be a single digit? What is the probability your 6-digit birthday will be the winning ticket? ) Complete parts (a) through (d) again under the assumption the order of the digits is irrelevant. How are your chances of winning affected? Better? Worse? Explain. f) How many ping-pong balls are needed in the container to produce an (approximately) equal chance of winning if the order of the ping-pong balls is irrelevant?Explanation / Answer
Number of tickets for 1% chance = 0.01 / 0.000001684 = 5938.24 = 5939.
e) Since the order of the digits is irrelevant we need to calculate combinations instead of permutations.
Probability of holding a winning ticket = 1 / 30C6 = 1 / 593775 = 0.000001684.
Since this value is bigger than the earlier value, the chances of winning are increased.
Number of tickets for 1% chance = 0.01 / 0.000001684 = 5938.24 = 5939.
Number of tickets for 10% chance = 5938.24 *10 = 59382.4 = 59383.
Number of tickets for 25% chance = 0.25 / 0.000001684 = 148456.06 = 148457.
Number of tickets for 50% chance = 0.5 / 0.000001684 = 296912.11 = 296913.
In all cases above, since fewer tickets need to be bought, the chances of winning are increased.
There are 15C6 ways to choose even numbers out of 30C6.
Probability of all even numbers = 15C6 / 30C6 = 5005 / 593775 = 0.0084
Probability that atleast one is odd = 1 - 0.0084 = 0.9916
There are 10C6 ways to choose single digit numbers out of 30C6.
Probability of all single digit numbers = 10C6 / 30C6 = 210 / 593775 = 0.00035.
Probability of six digit winning ticket = 1 / 210 = 0.0047.
Since this value is greater than the earlier value, the chance of winning is increased.
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