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Does iR pay to ask for a raise? percentage who got one. According to the survey

ID: 2926422 • Letter: D

Question

Does iR pay to ask for a raise? percentage who got one. According to the survey for a raise received the raise. If a at random answers to three decimal places.) A national survey of heads of households showed the percentage of those who asked fora raise and the of the men interviewed, 18% had asked for a raise and 55% of the men who had asked man is selected at random from the survey populatien of men, find the following probebities. (Enter your (a) man asked for a raise) (b) P(man received raise, given he asked for one) (c) P(man asked for raise and received raise SR01S. There is money to send two of nine city council members to a conference in members to go to the conference by a random process. How many dfferent combinations of two council members can be selected from the nine who want to go to the conference? Honolulu. All want to go, so they decide to choose the A student must satisty the literature, social science, and philosophy requirements this semester. There are four sterature courses to select from, three secial science courses, science, and philosophy courses and two philosophy courses. Make a tree diagram showing all the possible sequences of literature, social bnt

Explanation / Answer

Question 7:

a) Here we are given that 18% of the men asked for a raise. Therefore:

P( man asked for a raise ) = 0.18

b) Also we are given that 55% of the men who had asked for a raise received the raise which means that:

P( man received raise | man asked for a raise ) = 0.55

Therefore 0.55 is the required probability here.

b) Also we are given that 55% of the men who had asked for a raise received the raise which means that:

P( man received raise | man asked for a raise ) = 0.55

Using bayes theorem, we get:

P( man received raise and man asked for a raise ) = P( man received raise | man asked for a raise ) P( man asked for a raise )

P( man received raise and man asked for a raise ) = 0.55*0.18 = 0.099

Therefore 0.099 is the required probability here.

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