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A random sample of 131 patients, suffering from a particular disease are given a

ID: 2923371 • Letter: A

Question


A random sample of 131 patients, suffering from a particular disease are given a new medicine. 100 of the patients report an improvement in their condition.

b. Find the minimum sample size required if we want to estimate the improvement rate of this medicine to within 3% with 90% confidence if it is known that the improvement rate is between 70% and 90%. Enter an integer. You must round up.

Tries 0/5

c. Find the minimum sample size required if we want to estimate the improvement rate of this medicine to within 3% with 90% confidence if we do not make any assumptions about the improvement rate.

Tries 0/5

d. Construct a 90% confidence lower bound for the overall improvement rate. Round your answer to 3 decimal places.

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e. Construct a 95% confidence upper bound for the overall improvement rate. Round your answer to 3 decimal places.

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f. The company that manufactures this medicine claims an 80% improvement rate. Based on your answer to part (e), do you find this claim believable? Explain your answer.

DONT GIVE WRONG ANSWER
IF YOU CANT ANSWER DONT JUST RANDOMLY TRY TO A NSWRR

Explanation / Answer

b)

for improvement rate estimate p=0.8

margin of error E =003

and for 90% CI ; z =1.645

hence sample size =p(1-p)*(Z/E)2 =~632

c) for no available estimate p=0.5

hence sample size =p(1-p)*(Z/E)2 =~752

d)for proportion p=100/131 =0.7633 ; n=131

hence std error =(p(1-p)/n)1/2 =0.037

for 90% lower bound z = -1.28

hence 90% confidence lower bound for the overall improvement rate = sample proportion +z*Std error =0.7158~71.58%

e)

or 95% upper bound z = 1.6449

hence 95% confidence upperr bound for the overall improvement rate = sample proportion +z*Std error =0.8244~82.44% ;

f)as our 95% confidence upperr bound for the overall improvement rate is greater then 80%

we  find this claim believable.

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