te ra us arug use from this study and interpret the result. is study and inter r

Question

te ra us arug use from this study and interpret the result. is study and inter ris of developing TB in relation to the use ot inrav .5 Set 6 Mutually exclusive and independence ach member of a certain population of unhealthy patients has a risk of heart attack at levels low, medium, or high; and a risk of stroke at levels low, medium or high. The proportions of patients within each of the 9 categories are given in the following table. Risk of Risk of stroke heart attack Low Medium High 0.13 0.15 0.12 Low Medium 0.02 0.30 0.08 High 0.05 0.05 0.10 ose that one patient is randomly chosen from this population. If the howen a medium or high risk of heart attack, what is the 85 only a low risk of a stroke? (b) Suppose that one patient is randomly chosen from this popalation. Whieh of te ollaci chosen patient patient probability that the has statements are true? i. The events chosen patient has a low risk of heart attack and chosen patient bas high risk of stroke are independent. ii. The events chosen patient has a medium risk of heart attack and chosen patient b a medium risk of a stroke are mutually exclusive. The events chosen patient has a low risk of stroke and chosen patient has a high risk of a stroke are mutually exclusive. iii. (c) Suppose that two patients are randomly chosen from this population and that this pop- ulation is large. What is the probability that both patients have a high frik of strole nnn ndomlv selected car accident vehicles by

Explanation / Answer

Here' how to answer the questions:

a. P( patient has low stroke risk given patient has medium or high risk of HA)

= (.13+.02+.05)/(.02+.30+.08+.05+.05+.10) = .3333

b.

i) P(low risk of HA and high risk of stroke) = .05........1

P(low risk of HA)*P(high risk of stroke) = (.13+.15+.12)*(.12+.08+.10) =.12..........2

If the 2 events were independent then P(A and B) = P(A)*P(B)

Since this is .12 is not queal to .05 we conclude that events aren't independent

ii) No. Since they share a probability of .30 they aren't ME.

iii) Yes. Since the same patient can't have different stroke risk

c) P( 2 patients have high stoke risk) = ?. When population is huge, then we can conclude that the events are independent. So, P( 2 patients have high stoke risk) = (.13+.02+.05)*(.13+.02+.05) = .04

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.