Movie companies need to predict the gross receipts of individual movies after a
ID: 2921368 • Letter: M
Question
Movie companies need to predict the gross receipts of individual movies after a movie has debuted. The accompanying results are the first weekend gross, the national gross, and the worldwide gross (in millions of dollars) of six movies. Complete parts (a) through (d) below. Click the icon to view the gross receipts of the six movies a. Compute the covariance between first weekend gross and national gross, first weekend gross and worldwide gross, and national gross and worldwide gross. Compute the covariance between first weekend gross and national gross. cov(X,Y)- (Round to four decimal places as needed.) Compute the covariance between first weekend gross and worldwide gross. cov(XY)- (Round to four decimal places as needed.) Compute the covariance between national gross and worldwide gross. cov(X,Y)- (Round to four decimal places as needed.) b. Compute the coefficient of correlation between first weekend gross and national gross, first weekend gross and worldwide gross, and national gross and worldwide gross Compute the coefficient of correlation between first weekend gross and national gross. Gross receipts of six movies | | (Round to four decimal places as needed.) Compute the coefficient of correlation between first weekend gross and worldwide gross. r- (Round to four decimal places as needed.) Compute the coefficient of correlation between national gross and worldwide gross. rRound to four decimal places as needed.) Click to select your answer(s). First National Worldwide Weekend Gross Gross Title Mov vie A90.044 317.339 976.152 88.867 261.453 878.362 C 93.221 249.126 795.194 Movie D 02.027 290.417 896.603 Movie E 77.397 292.507 938.083 Movie F77.803 301.897 934.593 Movie B MovieExplanation / Answer
PART A.
covariance between first weekend and the national gross
calculation procedure for correlation
sum of (x) = x = 529.359
sum of (y) = y = 1712.739
sum of (x^2)= x^2 = 47148.5316
sum of (y^2)= y^2 = 492169.6536
sum of (x*y)= x*y = 150790.8233
to caluclate value of r( x,y) = covariance ( x,y ) / sd (x) * sd (y)
covariance ( x,y ) = [ x*y - N *(x/N) * (y/N) ]/n-1
= 150790.8233 - [ 6 * (529.359/6) * (1712.739/6) ]/6- 1
= -53.024
ii. covariance between first weekend and the world gross
calculation procedure for correlation
sum of (x) = x = 529.359
sum of (y) = y = 5418.987
sum of (x^2)= x^2 = 47148.5316
sum of (y^2)= y^2 = 4914086.7579
sum of (x*y)= x*y = 476879.4698
to caluclate value of r( x,y) = covariance ( x,y ) / sd (x) * sd (y)
covariance ( x,y ) = [ x*y - N *(x/N) * (y/N) ]/n-1
= 476879.4698 - [ 6 * (529.359/6) * (5418.987/6) ]/6- 1
= -203.1311
iii. covariance between national and the world gross
calculation procedure for correlation
sum of (x) = x = 1712.739
sum of (y) = y = 5418.987
sum of (x^2)= x^2 = 492169.6536
sum of (y^2)= y^2 = 4914086.7579
sum of (x*y)= x*y = 1554460.4004
to caluclate value of r( x,y) = covariance ( x,y ) / sd (x) * sd (y)
covariance ( x,y ) = [ x*y - N *(x/N) * (y/N) ]/n-1
= 1554460.4004 - [ 6 * (1712.739/6) * (5418.987/6) ]/6- 1
= 1262.5563
PART B.
i.regression b/w first week and the national gross
to calculate r( x,y) = -53.024/ (SQRT(1/6*150790.823342-(1/6*529.359)^2) ) * ( SQRT(1/6*150790.823342-(1/6*1712.739)^2)
=-53.024 / (8.6124*23.2994)
=-0.2642
value of correlation is =-0.2642
ii. regression b/w first week and the world gross
to calculate r( x,y) = -53.024/ (SQRT(1/6*150790.823342-(1/6*529.359)^2) ) * ( SQRT(1/6*150790.823342-(1/6*1712.739)^2)
=-53.024 / (8.6124*23.2994)
=-0.2642
value of correlation is =-0.2642
iii. regression b/w national and the world gross
to calculate r( x,y) = 1262.5563/ (SQRT(1/6*1554460.400411-(1/6*1712.739)^2) ) * ( SQRT(1/6*1554460.400411-(1/6*5418.987)^2)
=1262.5563 / (23.2994*57.5182)
=0.9421
value of correlation is =0.9421
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