1. a family has two children; record the genders in order ofbirth A){b,g}, equal
ID: 2918599 • Letter: 1
Question
1. a family has two children; record the genders in order ofbirthA){b,g}, equally likely
B) {bb,bg,gb,gg} not equally likely
C) {bb,bg,gg} equally likely
D) {bb,bg,gb,gg} equally likely
E) {bb,bg,gb,gg} no equally likely
2.a family has two children; record the possbile genders(not thesame as above)
A) {b,g} equally likely
B) {bb,bg,gg} not equally likely
C) {bb,bg,gg} equally likely
D) {bb,bg,gb,gg} equally likely
E) {bb,bg,gb,gg} not equally likely
3.accroding to national telecon information 50.5% of us house holdshad internat access in 2001. what is the probabily that four randomselected us households ass had internet access in 2001?
A) 93.5
B)50.5
C)49.5
D)12.6
E)6.5
4. an ice cream stand reports 12% of the cones they sell are jumbosize. you want to see what a jumbo size looks like so you stand andwatch the sales. what is the probabilty that the first jumbo coneis the fourth cone you se them sell?
A)40
B)60
C)93
D)8
E)33
5. a survey revealed that 31% of people are entertained by readingbooks, 43% are ebtertained by watching tv and 26% by both books andtv. what is the probaibly that a person will be entertained byeither books or tv?
A)1
B).74
C).48
D).26
E).14
6. a group of volenteers for a clincical trial consists of 80 womenand 74 men. 20 of the women and 17 of the men have high bloodpreasure. If one of the volenteers is selceted at random find theprob that the person is a man given that they have highblood preasure
A).230
B).110
C).481
D).459
E).240
7)all bags entering a reasearch facility are screened. 97% of thebags that contains fobidden material trigger an alarm. 15% of thebags that do not contain forbidden material also trigger alarm. If1 out of every 1000 bags entering the building contains fobiddenmaterial, what is the prob that a bag that triggers the alarm willaccually contain forbidden materall?
A).14550
B).00097
C).03000
D).97000
E).00640
Explanation / Answer
1. a family has two children; record the genders in order ofbirth A){b,g}, equally likely B) {bb,bg,gb,gg} not equally likely C) {bb,bg,gg} equally likely D) {bb,bg,gb,gg} equally likely E) {bb,bg,gb,gg} no equally likely D true 2.a family has two children; record the possbile genders(not thesame as above) A) {b,g} equally likely B) {bb,bg,gg} not equally likely C) {bb,bg,gg} equally likely D) {bb,bg,gb,gg} equally likely E) {bb,bg,gb,gg} not equally likely C true 3.accroding to national telecon information 50.5% of us house holdshad internat access in 2001. what is the probabily that four randomselected us households ass had internet access in 2001? A) 93.5 B)50.5 C)49.5 D)12.6 E)6.5 ans= (.505)4=.065 or 6.05% E 4. an ice cream stand reports 12% of the cones they sell are jumbosize. you want to see what a jumbo size looks like so you stand andwatch the sales. what is the probabilty that the first jumbo coneis the fourth cone you se them sell? A)40 B)60 C)93 D)8 E)33 ans = (.88)3(.12)=.081770 = 8% ans D 5. a survey revealed that 31% of people are entertained by readingbooks, 43% are ebtertained by watching tv and 26% by both books andtv. what is the probaibly that a person will be entertained byeither books or tv? A)1 B).74 C).48 D).26 E).14 ans= P(read)+p(tv)-P(both)=.31+.53-.26-=.58 6. a group of volenteers for a clincical trial consists of 80 womenand 74 men. 20 of the women and 17 of the men have high bloodpreasure. If one of the volenteers is selceted at random find theprob that the person is a man given that they have highblood preasure A).230 B).110 C).481 D).459 E).240 as= P(Man|High)= P(Man and High)/P(High)=(17/154)/(37/154)=.459 ans D 7)all bags entering a reasearch facility are screened. 97% of thebags that contains fobidden material trigger an alarm. 15% of thebags that do not contain forbidden material also trigger alarm. If1 out of every 1000 bags entering the building contains fobiddenmaterial, what is the prob that a bag that triggers the alarm willaccually contain forbidden materall? A).14550 B).00097 C).03000 D).97000 E).00640 g=good,b=bad, a=alarm p(g)=.999 P(b)=.001 P(a and b)=p(b)*P(a|b)=.001(.97)=.00097 P(a and g)= P(g)*P(a|g)=.999(.15)==.14985 P(b|a)=.00097/(.00097+.14985)=.060795 closest E but...
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