Specifications for a part for a DVD player state that the partshould weigh betwe

Question

Specifications for a part for a DVD player state that the partshould weigh between 24 and 25 ounces. The process that producesthe parts yields a mean of 24.5 ounces and a standard deviation of0.2 ounce. The distribution of output is normal.

What percentage of parts will not meet the wight specs?


Specifications for a part for a DVD player state that the partshould weigh between 24 and 25 ounces. The process that producesthe parts yields a mean of 24.5 ounces and a standard deviation of0.2 ounce. The distribution of output is normal.

What percentage of parts will not meet the wight specs?

Explanation / Answer

mean , = 24.5 standard deviation , =0.2 Specifications for a part for a DVD player state that the partshould weigh between 24 and 25 ounces. hence as per normal distribution, - z =24 hnce, 24.5-z * 0.2 = 24 hence, z = 2.5 from z table, the p value corresponding to 2.5 is 0.9938.hence percentage of parts that meet the wight specs =99.38% hence, percentage of parts will not meet the wight specs=100-99.38= 0.62%

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.