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A math teacher with no fashion sense picks his outfits atrandom each day. Each o

ID: 2914662 • Letter: A

Question

A math teacher with no fashion sense picks his outfits atrandom each day. Each outfit consists of a shirt, a pair of pants,and a pair of shoes. One day, he has 5 different shirts, 4different pairs of pants, and 3 different pairs of shoes to pickfrom. Since he has no fashion sense, he is equally likely to pickany shirt, pants, or shoes. A) How many possible outfits could he make? B) What is the probability that a specific outfit ischosen? C) He decides he likes a certain shirt and chooses it. Howmany outfits are now available to him? D) What is the probability he will complete the outfit with aspecific pair of pants and shoes? Please show how you got the answer! I will rate lifesaver tothe first person! Thanks! A math teacher with no fashion sense picks his outfits atrandom each day. Each outfit consists of a shirt, a pair of pants,and a pair of shoes. One day, he has 5 different shirts, 4different pairs of pants, and 3 different pairs of shoes to pickfrom. Since he has no fashion sense, he is equally likely to pickany shirt, pants, or shoes. A) How many possible outfits could he make? B) What is the probability that a specific outfit ischosen? C) He decides he likes a certain shirt and chooses it. Howmany outfits are now available to him? D) What is the probability he will complete the outfit with aspecific pair of pants and shoes? Please show how you got the answer! I will rate lifesaver tothe first person! Thanks!

Explanation / Answer

a) There are 5 choices for the shirt, 4 choices for the pants and3 choices for the shoes Thus, there are 5x4x3 = 60 ways b) Since each outfit is equally probable, and we have found thereare 60 ways, probability = 1/60 for a specific outfit c) There are 4 choices for the pants and 3 choices for theshoes Thus, there are 4x3 = 12 ways d) Since there are 12 ways found in part c, the probability tocomplete the outfit is 1/12
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