(a) John wants to paint four rooms in his house, each adifferent color and he ma

Question

(a) John wants to paint four rooms in his house, each adifferent color and he may choose from seven different colors ofpaint. How many color combinations are possible for the fourrooms?

(b) If there are 25 names in a hat, 15 girl’s names and 10boy’s names, what is the probability that a name drawn atrandom will be

                                           I.      a girl’sname

                                        II.      a boy’sname

                                      III.      not agirl’s name

                                     IV.      not aboy’s name

Explanation / Answer

(a) Combinations = 7P4 = 840 ( I assume therecan be arrangement of colours for the same combination in fourrooms) (b) I) 15/25 = 0.6 II) 10/25 = 0.4 III) 1 - 15/25 = 0.4 IV) 1 - 10/25 = 0.6 Hope this helps!

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.