(a) In part B of this experiment, you will use copper(II) sulfate pentahydrate.

Question

(a) In part B of this experiment, you will use copper(II) sulfate pentahydrate. What is the molar mass of this compound? g/mol

(b) How much of this compound must be weighed to make 175.0 mL of a 0.15 M solution?____ g

(c) How many mL of the 0.15 M solution should be diluted to prepare 150.0 mL of a 0.050 M solution?

Explanation / Answer

----->249.68 + ( 5 x 18.02)= 339.78 g/mol ----------->moles needed = 0.150 L x 0.15 M=0.0225 ----------->mass needed = 0.0225 x 249.68=5.62 ---------->249.68 : 339.78 = 5.62 : x ----------->x = 7.65 g

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