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Probability: The following shows the distribution of a group of elementaryschool

ID: 2913545 • Letter: P

Question

Probability:

The following shows the distribution of a group of elementaryschool children according to their academic performance and thequality of their nutritional status.

                                   NUTRITIONAL STATUS

                                        _________________________________________________

Academics                             Poor(P)                       Good(G)                     Excellent(E)

                                                                                                                                    

        Low(L)                          145                              70                               65                           

        Medium(M)                     60                             175                             155        

        High(H)                           25                               55                            250     

                                                

Using the information presented in the Nutritional Status table,determine what the probability is that a child picked at randomfrom this group:

1) Had a low rating on academic performance.

                       

2) Was rated excellent in terms of their nutritional status.

                       

3) Had a low academic performance and an excellent nutritionalstatus.

                        

4) Had low academic performance given that he or she hadexcellent nutritional status.

            

5) Had high academic performance or excellent nutritionalstatus.

Explanation / Answer

total number of students = 1000 1) Had a low rating on academic performance.
145 + 70 + 65 = 280 out of1000     280/1000 = .28 or 28 % 2) Was rated excellent in terms of their nutritionalstatus.
   65+155+250=470 out of 1000= .47 or 47% 3) Had a low academic performance and an excellent nutritionalstatus.
65 =65 /100 = .065 or 6.5 % 4) Had low academic performance given that he or she hadexcellent nutritional status. 65 out of 470 = .1383 or 13.83 %             
5) Had high academic performance or excellent nutritionalstatus 25 + 55 + 250 + 65 + 155 = 550 out of 100 = .55or 55%        
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