7. Two ships leave a harbor at the same time. On ship travels on a bearing of at

Question

7. Two ships leave a harbor at the same time. On ship travels on a bearing of at 14 miles per hour. The other ship travels on a bearing of N75°E at 10 miles per hour. How far apart will the ships be after three hours? Round to the nearest tenth of a mile. S12°W A plane leaves airport A and travels 580 miles to airport B on a bearing of The plane later leaves airport B and travels to airport C 400 miles away on a bearing of S74°E, Find the distance from airport A to airport C to the nearest tenth of a mile. 8. N34°E

Explanation / Answer

7) Two ships are travelling in opposite directions that means one is towards north-east and another is towards south-west. So, We have to add both the speeds. According to the formula, Speed (S) = Distance (D) / Time (T)

Here S1 = 14 m/h and S2 = 10 m/h T = 3hrs

So, D = (S1 + S2) * T = (14 +10) * 3 = 24 *3 = 72 miles (ANSWER)

Tenth of a mile = 72 miles nearest to 70 miles (ANSWER)

8) Distance(D1) between airport A and airport B is 580 miles and distance(D2) between airport B and airport C is 400 miles.

So, Distance between airport A to airport C = D1 + D2 = 580 + 400 = 980 miles

Tenth of a mile = 980 miles nearest 1000 miles (ANSWER)

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