A new motel chain in the U.S. is interested in the amount of time Americans spen
ID: 2907701 • Letter: A
Question
A new motel chain in the U.S. is interested in the amount of time Americans spend in the shower. The U.S. Environmental Protection Agency reports that the average shower lasts 8.2 minutes. The distribution for these times appears to be normally distributed. If the standard deviation for these times is 7.9 minutes, find the shower length that separates the longest ten percent of showers from the remaining ninety percent of showers. (Use the Z value in the standard normal table that is closest to the required probability. Do not round any other intermediate calculations. Enter your answer as a decimal rounded to two places)
Shower length = ____ minutes
Explanation / Answer
Ans:
Given that
mean=8.2
standard deviation=7.9
We have to find actually 90th percentile :
P(Z<=z)=0.9
z=normsinv(0.9)=1.2816
P90=8.2+1.2816*7.9=18.32 minutes
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