A new landowner has a triangular piece of flat land she wishes to fence. Startin

Question

A new landowner has a triangular piece of flat land she wishes to fence. Starting at the west corner, she measures the first side to be 80 m long and the next to be 105 m -- these sides are represented as displacement vectors A and B in Figure 3.26, where ?1=19

A new landowner has a triangular piece of flat land she wishes to fence. Starting at the west corner, she measures the first side to be 80 m long and the next to be 105 m -- these sides are represented as displacement vectors A and B in Figure 3.26, where ?1=19 degree , and ?2=11 degree . She then correctly calculates the length and orientation of the third side C. What is her result? m degree south of west

Explanation / Answer

A) Y = 80 * SIN 20 = - 27.36
A) X = 80 * COS 20 = 75.175
B) Y = 105 * COS 10 = 103.4
B) X = 105 * SIN 10 = -18.23
TOTAL Y = 103.4 - 27.36 = +76.04
TOTAL X = 75.175 - 18.23 = +56.945
Third Side : C) = SQRT (76.04.^2 + 56.945^2) = 94.999Meters length
Third Side : C) Angle = ARC TAN 76.04 / 56.945 = 53.17 degrees North of Due West
from the West Corner

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