Use the following POM crashing output to answer Q39 - Q40. Times are in DAYS. Cr
ID: 2903822 • Letter: U
Question
Use the following POM crashing output to answer Q39 - Q40. Times are in DAYS.
Crashing Solution
Activity
Normal time
Crash time
Normal Cost
Crash Cost
Crash cost/pd
Crash by
Crash cost
Project
26
17
A
7
6
1500
1800
300
1
300
B
12
9
3000
4050
350
1
350
C
9
6
2500
3700
400
2
800
D
12
6
2800
5200
400
6
2400
E
3
1
500
1100
300
2
600
F
1
1
0
0
0
0
0
G
3
1
600
1500
450
2
900
H
3
2
300
750
450
0
0
I
4
4
0
0
0
0
0
TOTALS
11200
5350
Crashing Solution
Project time
Period cost
Cumulative cost
A
B
C
D
E
F
G
H
I
26
0
0
25
300
300
1
24
400
700
1
1
23
400
1100
1
2
22
400
1500
1
3
21
450
1950
1
3
1
20
450
2400
1
3
2
19
700
3100
1
4
1
2
18
1100
4200
1
1
5
2
2
17
1150
5350
1
1
2
6
2
2
1) What would you do to crash this project to 20 days?
A. Crash A
Crashing Solution
Activity
Normal time
Crash time
Normal Cost
Crash Cost
Crash cost/pd
Crash by
Crash cost
Project
26
17
A
7
6
1500
1800
300
1
300
B
12
9
3000
4050
350
1
350
C
9
6
2500
3700
400
2
800
D
12
6
2800
5200
400
6
2400
E
3
1
500
1100
300
2
600
F
1
1
0
0
0
0
0
G
3
1
600
1500
450
2
900
H
3
2
300
750
450
0
0
I
4
4
0
0
0
0
0
TOTALS
11200
5350
Explanation / Answer
1.
as shown in 2nd table
at 20 days duration
A for 1 day, D for 3 day and G for 2 day crashed.
2.
Option A: Crash project time to 20 days, which saves $600 compared to normal completion time of 26 days
is correct
Days Cost due to crashing Panelty Net Saving 17 5350 0 5350 -850 18 4200 500 4700 -200 19 3100 1000 4100 400 20 2400 1500 3900 600 21 1950 2000 3950 550 22 1500 2500 4000 500 23 1100 3000 4100 400 24 700 3500 4200 300 25 300 4000 4300 200 26 0 4500 4500 0Related Questions
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