I have already done most of the calculations, just looking for someone to help m
ID: 2902334 • Letter: I
Question
I have already done most of the calculations, just looking for someone to help me interpret them please. I already know the answer to question (i), just wanted to give you a better idea of the whole problem.
Assume the Boolean matrix below is MR and that MR represents the relation R where R represents the connecting flights that an airline has between 4 cities: a, b, c, and d. so there is a 1 in row x column y iff there is a connecting flight between (from) city x and (to) city y. That is, the rows of the matrix represent the cities of the origins of the flight and the columns represent the destination cities. Let the 0 in row d and column d stand for planes cannot
Explanation / Answer
a = Manchester
b = Boston
c = Chicago
d = Denver
Given Matrix is :
a b c d
a 1 1 0 0
b 0 1 1 0
c 0 0 1 1
d 1 1 0 0
(a)
No, there is no flight from Manchester to Chicago.
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(b)
MR2 =
1 1 1 0
0 1 1 1
1 1 1 1 *
1 1 1 0
MR3 =
1 1 1 1
1 1 1 1
1 1 1 1
1 1 1 1
The above two matrices were obtained using Boolean Arithmetic.
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(c)
Now, MR matrix has been renamed as matrix A.
A2 =
1 2 1 0
0 1 2 1
1 1 1 1 *
1 2 1 0
A3 =
1 3 3 1
1 2 3 2
2 3 2 1
1 3 3 1
The above two matrices were obtained using Normal Arithmetic.
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