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I have already done most of the calculations, just looking for someone to help m

ID: 2902334 • Letter: I

Question

I have already done most of the calculations, just looking for someone to help me interpret them please. I already know the answer to question (i), just wanted to give you a better idea of the whole problem.

Assume the Boolean matrix below is MR and that MR represents the relation R where R represents the connecting flights that an airline has between 4 cities: a, b, c, and d. so there is a 1 in row x column y iff there is a connecting flight between (from) city x and (to) city y. That is, the rows of the matrix represent the cities of the origins of the flight and the columns represent the destination cities. Let the 0 in row d and column d stand for planes cannot

Explanation / Answer

a = Manchester

b = Boston

c = Chicago

d = Denver

Given Matrix is :

a b c d

a 1 1 0 0

b 0 1 1 0

c 0 0 1 1

d 1 1 0 0

(a)

No, there is no flight from Manchester to Chicago.

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(b)

MR2 =

1 1 1 0

0 1 1 1

1 1 1 1 *

1 1 1 0

MR3 =

1 1 1 1

1 1 1 1

1 1 1 1

1 1 1 1

The above two matrices were obtained using Boolean Arithmetic.

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(c)

Now, MR matrix has been renamed as matrix A.

A2 =

1 2 1 0

0 1 2 1

1 1 1 1 *

1 2 1 0

A3 =

1 3 3 1

1 2 3 2

2 3 2 1

1 3 3 1

The above two matrices were obtained using Normal Arithmetic.

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