In order to determine if the vector w = (2, -6, 3) is a linear combination of th
ID: 2895629 • Letter: I
Question
In order to determine if the vector w = (2, -6, 3) is a linear combination of the vectors u = (1, -2, -1) and v = (3, -5, 4) an equation au + bv = w was written to solve for constants ‘a’ and ‘b’. An echelon form of the augmented coefficient matrix led to no solution. Which of the following can be concluded from the above information?
1) w is not a linear combination of u and v.
2) u, v and w are linearly independent.
3) v is not a linear combination of u and w.
Statement (1) alone is true
Statement (2) alone is true
Statement (3) alone is true
Statements (1) and (2) are true
Statements (1) and (3) are true
Statements (2) and (3) are true
All the statements are true
All the statements are false
A.Statement (1) alone is true
B.Statement (2) alone is true
C.Statement (3) alone is true
D.Statements (1) and (2) are true
E.Statements (1) and (3) are true
F.Statements (2) and (3) are true
G.All the statements are true
H.All the statements are false
Explanation / Answer
option D) Statement 1 and 2 are true.
If there is no solution for augmented matrix, then there is no relationship between the given vectors w, u , v.
=> w, u , v are linearly independent.
=> w is not a linear combination of u and v.
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