Given the Taylor series sigma^infinity_n = 0 f^(n) (-9)/n ! (x + 9)^n around whi

Question

Given the Taylor series sigma^infinity_n = 0 f^(n) (-9)/n ! (x + 9)^n around which point is this Taylor series centred? State only the numerical value. e.g. - 2 This question accepts numbers or formulas. The Taylor series expansion for f(x) = e^2x around the point a = 6 is given by sigma^infinity_n = 0 2^n e^12/n ! (x - 6)^n True False Find the first order approximation (i.e. up to n = 1 of the Maclaurin series expansion) for sin (7x). State only the resulting approximation e.g. 3-2x. You must use x (lower case) as your variable.

Explanation / Answer

1) Taylors series centered

Answer = -9

2) Taylors series expansion of e^2x

Answer = True

3) Approximation of sin7x

Answer = 7x

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