1) Find an equation of the tangent line to the curve at the given point. y = x3

ID: 2890890 • Letter: 1

Question

1) Find an equation of the tangent line to the curve at the given point. y = x3 2x + 2, (3, 23)

2)If the tangent line to y = f(x) at (5, 2) passes through the point (0, 1), find f(5) and f'(5).

3) If f(x) = 5x2 x3, find f'(1) and use it to find an equation of the tangent line to the curve y = 5x2 x3 at the point (1, 4).

4) Find f'(a). f(x) = 2x2 5x + 4

5) Find the derivative of the function using the definition of derivative. f(t) = 4t 5t2f'(t) = ?

- State the domain of the function. (Enter your answer using interval notation.)

- State the domain of its derivative. (Enter your answer using interval notation.)

thank u so much whoever can help. im so lost on all of this

f(5) = f'(5) =

1. y=x3-2x+2

y'= 3x2-2

At (3,23)

y'= 3(3)2-2 =25

Using point slope form which is

y-y1=m(x-x1)

y-23=25(x-3)

y=25x-52

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