This question has several parts that must be completed sequentialy. If you skip

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This question has several parts that must be completed sequentialy. If you skip a part of the question, you wil not receive any points for the skipped part, and you wil not be able to come back to the skigped part A spherical balloon is being inflated and the radius of the baloon is incressing at a rate of 9 cm/s Express the radius r of the balloon as a function of the time t (in secends). The radius of the baloon can be written as a function of ime. no, we know the radius increases em each second. For example, after 2 seconds, the radius will be 18 cm, and after 3 seconds, the radius wil be tt V is the volume of the balloon as a function of the radus, find Vo r The volume o, . sener" s given by v- function is therefore However, we found earlier that rn.se, and the composite

Explanation / Answer

Radius is increasing at 9cm/sec

After one sec, radius =9 cm

After 2 sec, radius=18cm

After three sec, radius=27cm

Therefore after t sec, radius

r(t)= 9 t sec

b.(Vor)(t)=V(r(t)) = V(9t) = (4/3) pi (9t)3 =972 pi t3

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