5 points SCalcET8 4.3011 Consider the equation below. (If an answer does not exi
ID: 2888308 • Letter: 5
Question
5 points SCalcET8 4.3011 Consider the equation below. (If an answer does not exist, enter DNE.) f(x) -s0x2 2 (a) Find the interval on which f is increasing. (Enter your answer using interval notation.) Find the interval on which f is decreasing. (Enter your answer using interval notation.) (b) Find the local minimum and maximum values of f. local minimum value local maximum value (c) Find the inflection points. (x, y) = (smaller x-value) (x, y) = largerx-value) Find the interval on which f is concave up. (Enter your answer using interval notation.) Find the interval on which f is concave down.(Enter your answer using interval notation.) Need Help?WchTalk to Tutor Talk to a TutorExplanation / Answer
y= x^4-50x^2+2
Find derivative as
dy/dx = 4x^3 -100x
To find critical point, set dy/dx =0 and then solve for x as
4x^3 -100x = 0
4x (x² -25) =0
4x (x+5) (x-5) = 0
x = -5,0, 5
Find second derivative as
y" = 12x² -100
12x² -100 =0
x² = 100/12
x² = 25/3
x = -5/3 , 5/3
a)
Increasing on (-5,0)U(5,)
Decresaing on (-, -5)U(0,5)
b)
local minimum is -623
local maximaum is 2
c)
Inflection points are
(-5/3 , -3107/9)
(5/3 , -3107/9)
Concave up : (-, -5/3) U(5/3 ,)
Concave down : ( -5/3 , 5/3)
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