DChapter6-ax/WeBWorK . × YG find the min × The Study × AD Calculus l work.as.uky

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DChapter6-ax/WeBWorK . × YG find the min × The Study × AD Calculus l work.as.uky.edu/webwork2/MA 123S18/HW14/3/?key C5dSWOdok2WxspowYRXgicyXy4tkLdIG&eff; MATHEMATICAL ASSOCIATION OF AMERICA webwork ma123s18 / hw1413 W14: Problem3 Previous Problem Problem List Next Problem (1 point) Find the minimum value of g(t) -48t 8 on the interval -2,5 Minimum value is Preview My Answers Submit Answers You have attempted this problem 6 times Your overall recorded score is 0%. You have unlimited attempts remaining Email instructor ch

Explanation / Answer

g(t) = t^3 -48t +8

Find derivative as

g'(t) = 3t² -48

find critical point as

g'(t) = 0

3t² -48 = 0

t² -16 = 0

(t+4) (t-4) = 0

t= 4 [ given -2<=t<=5]

Now find

f(-2) =96

f(4) =-120

f(5) =-107

Thus,

Minimum value is -120

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