The graph to the right shows the rate of inhalation of oxygen (in liters per min
ID: 2884539 • Letter: T
Question
The graph to the right shows the rate of inhalation of oxygen (in liters per minutes) by a person riding a bicycle very rapidly for 10 minutes Estimate the total volume of oxygen inhaled in the first 20 minutes after the beginning of the ride Use rectangles with widths of 1 minute 0 24 6 8 10 12 14 15 18 20 Mnutes Using the left endpoints, the total volume is about iters Using the right endpoints, the total volume is aboutiters (Type integers or decimals rounded to the nearest tenth as needed) Find the average of the volumes found using the left and right endpoints The total volume of oxygen inhaled is about liters Type an integer or decimal rounded to the nearest tenth as needed)Explanation / Answer
From the give graph , we will use reactngular approximation method.width of each rectangle is 1 minute and
total number of rectangle n=20.
The values has been determined graphically by aligning each x valyues with the corresponding y-values.
So, For the first part using leftend points:
A=0*1+1*2.4+1*2.6+1*2.7+1*2.8+1*2.9+1*3+1*3+1*3+1*3+1*0.5+1*0.45+1*0.40+1*0.35+1*0.30+1*0.25+1*0.23+1*0.21+1*0.19+1*0.17+=28.45L
So, For the second part using rightend points:
A=1*2.4+1*2.6+1*2.7+1*2.8+1*2.9+1*3+1*3+1*3+1*3+1*0.5+1*0.45+1*0.40+1*0.35+1*0.30+1*0.25+1*0.23+1*0.21+1*0.19+1*0.17+1*0.15=28.60L
Average Volume=(28.45+28.60)/2=28.525L
Left end points f(x) Right End Point f(x) 0 2.4 2.4 2.6 2.6 2.7 2.7 2.8 2.8 2.9 2.9 3 3 3 3 3 3 3 3 0.5 0.5 0.45 0.45 0.40 0.40 0.35 0.35 0.3 0.3 0.25 0.25 0.23 0.23 0.21 0.21 0.19 0.19 0.17 0.17 0.15Related Questions
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