Sy dvodx 5-7 sqrt(x) Step- x C Search Q&A; I Chegg. D WeBwork MTH3 Math P M Re:

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Sy dvodx 5-7 sqrt(x) Step- x C Search Q&A; I Chegg. D WeBwork MTH3 Math P M Re: MNWfeedback C https:// Fall2016 Fang/Chapter 1 Review/44/ wwm01.bcc.cuny.edu Apps Summer Research Inte D mth3 2016 fang Sy symbolab Math solve online Derivative Cal D weBWork: MTH31 Fe O 365F D 63 f6c0233ae7012c 1299c41c9cb67fb1c9 Homework Sets Chapter 1Review: Problem 44 Chapter Review Problem 44 Prev Up Next Password Ema Grades Entered Answer Preview Result Problems Problem 1 correct Problem 2 9.96 9.96 Correct Problem 3 Problem 4 At least one of the answers above is NOT CO Problem 5 Problem 6 32r cos (a) 1 on the interval 0 S S 1. The Intermediate value Theorem guarantees that 1 pt) Consider the function s a value c such that f (c) k for which values of c and k F Problem 7 n the following mathematical statements, giving an interval with non- ere zero length in each case. Problem 8 Problem 9 For every k in Problem 10 c 9.96 ere is a c in 1 Problem 11 such that f(c) k Problem 12 Problem 13 Problem 14 Note: You can earn partial credit on this problem. Problem 15 Problem 16 Preview Answers Submit Answers Problem 17 Problem 18 Your score was recorded. 618 PM 4) Ask me anything 2/18/2016

Explanation / Answer

we have given f(x)=3x-cosx+1 on [0,1]

lim x-->0 f(x)=lim x-->0 (3x-cosx+1) =3(0)-cos(0)+1 =0

lim x-->1 f(x)=lim x-->1 (3x-cosx+1) =3-cos(1)+1 =4.54030230587

lim x-->1/2 f(x)=lim x-->1/2 (3x-cosx+1)=3*(1/2)-cos(1/2)+1 =1.62241743811

The given function is continuous over the given interval [0,1]

So

f(0)=3(0)-cos(0)+1=0

f(1)=3(1)-cos(1)+1=3.45969769413   since cos(1) value is in radians

For every k in 0 <= k<=3.45969769413

there is c    in 0 <= c <=1

such that f(c)=k

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