whats the right answer and how do you solve for it? Find the local minimum and m
ID: 2878067 • Letter: W
Question
whats the right answer and how do you solve for it?
Find the local minimum and maximum values of f. Part 1 of 2 The function f(x) changes from increasing to decreasing at x = -5. Therefore, = 425 425 is a maximum a maximum Part 2 of 2 The function f(x) changes from decreasing to increasing at x = 4. Therefore, f(4) = 304 304 is a minimum a minimum. Find the inflection point. Find the interval on which f is concave up. Find the interval on which f is concave down. We have f'(x) = 6x^2 + 6x - 120, so f"(x) = 2 which equals 0 when (x, y) = (0, 6).Explanation / Answer
given f '(x) =6x2+6x-120
f "(x)=6*2x2-1+6*1 -0
f "(x)=12x+6
for inflection point f "(x)=0
12x +6=0
x =-1/2
inflection point at (-1/2, f(-1/2))
f is concave up when f "(x)>0
12x+6>0
x>-1/2
concave up in (-1/2,)
f is concave down when f "(x)<0
12x+6<0
x<-1/2
concave up in (-,-1/2)
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