whats the step by step solution for this problem A wood burning stove operates i

Question

whats the step by step solution for this problem

A wood burning stove operates in a room measuring 5 m by 5 m. The height of the room is 2.5 m. Clean air flows into the room at a rate of 30 m3/hr. The carbon monoxide (CO) in the room from the stove reaches a steady state concentration of 5 mg/m3. Assume that the stove is the only source of CO in the room (which can be modeled as a CMFR) and that CO is modeled as a conservative pollutant. (a) At what rate (mg/hr) is the stove emitting CO? (b) If the stove is turned off after reaching the steady state concentration, how long would it take for the CO concentration to be reduced to one half of the original steady state concentration (i.e. 2.5 mg/m3)?

Explanation / Answer

(a)..q*L/(uH) is the steady state concentration..........hence...5mg/m^3=q*L/(uH) ..where q is emmision rate ...L is length u is velocity and H is mixing height....putting these values we get q=2.5*u mg/m^3....u=30/(5*2.5).......Q=6mg/(m^3*Hr).......(B)The steady state answer for it is C(t)=q*L/(uH)[1-exp(-ut/L).........q*L/(uH) is the steady state concentration..........putting all values we get .......1.44hr.......

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.