A grocery store estimates that the weekly profit (in dollars) from the productio
ID: 2846322 • Letter: A
Question
A grocery store estimates that the weekly profit (in dollars) from the production and sale of x cases of soup is given by
P(x) = -5600 + 9.5x - 0.0017x2
and currently 1300 cases are produced and sold per week.
Use the marginal profit to estimate the increase in profit if the store prodcues and sells one additional case of soup per week.
f(x) = 6x + 2; [-1, 2]
f(x) = 2x2 - 16x + 27
f(x) = -3 - 7x; [-3, 1]
Find the derivative of the function and evaluate the derivative at the given x-value.
f(x) = 2x2 at x = 1
Differentiate.
f(x) = (5x + 4)2
f(x) = 0.2x2 - 2.4x + 5.9
f(x) = x3 - 3x2 + 1
A company estimates that the daily revenue (in dollars) from the sale of x cookies is given by
R(x) = 885 + 0.02x + 0.0003x2
Currently, the company sells 900 cookies per day.
Use marginal revenue to estimate the increase in revenue if the company increases sales by one cookie per day.
s(x) = -x2 - 20x - 19
f(x) = (-5x + 7)4
f(x) = 3 - 6x)140
Find the relative extrema of the function, if they exist.
f(x) = x2 - 4x + 7
Find the absolute maximum and absolute minimum values of the function, if they exist, over the indicated interval. When no interval is specified, use the real line (-?, ?).
f(x) = -21; [ -7, 7]
f(x) = -6x2 - 2x - 7
1.A grocery store estimates that the weekly profit (in dollars) from the production and sale of x cases of soup is given by
P(x) = -5600 + 9.5x - 0.0017x2
and currently 1300 cases are produced and sold per week.
Use the marginal profit to estimate the increase in profit if the store prodcues and sells one additional case of soup per week.
A) $7.29B) $3877.00
C) $5.52
D) $5.08
2. A)
B)
C)
D)
3.
f(x) = 6x + 2; [-1, 2]
A) There are no absolute extrema.B) Absolute maximum: 14, absolute minimum: -4
C) Absolute maximum: -1, absolute minimum: 2
D) Absolute maximum: 12, absolute minimum: -6
4.
f(x) = 2x2 - 16x + 27
A) Relative minimum at ( 5, -4)B) Relative maximum at ( -4, 5)
C) Relative minimum at ( -5, 4)
D) Relative minimum at ( 4, -5)
5.
f(x) = -3 - 7x; [-3, 1]
A) Absolute maximum: -10, absolute minimum: -24B) Absolute maximum: 18, absolute minimum: -10
C) Absolute maximum: 24, absolute minimum: -4
D) There are no absolute extrema
6.
Find the derivative of the function and evaluate the derivative at the given x-value.
f(x) = 2x2 at x = 1
A) f ' (x) = 2x; f ' (1) = 2B) f' (x) = 4x; f' (1) = 4
C) f' (x) = 4x; f' (1) = 2
D) f' (x) = 4x2; f' (1) = 4
7. A)
B)
C)
D)
8. f(x) = 5x + 9 at x = 2 A) f'(x) = 0; f'(2)=0
B) f' (x) = 5; f' (2) = 5
C) f'(x) = 9; f'(2) = 9
D) f'(x) = 5x; f'(2) = 10
9.
Differentiate.
f(x) = (5x + 4)2
A) f'(x) = 10(5x + 4)2B) f'(x) = 2(5x + 4)
C) f'(x) = 5(5x + 4)
D) f'(x) = 10(5x + 4)
10.
f(x) = 0.2x2 - 2.4x + 5.9
A) Relative maximum at ( 6, -1.3)B) Relative minimum at ( 6, -1.3)
C) Relative minimum at ( 6, 0)
D) Relative minimum at ( -6, 27.5)
11.
f(x) = x3 - 3x2 + 1
A) Relative maximum at (2, -3)B) Relative maximum at (0, 1); relative minimum at (2, -3)
C) Relative maximum at (-2, -19); relative maximum at (0, 1)
D) Relative minimum at (0, 1); relative maximum at (2, -3)
12.
A company estimates that the daily revenue (in dollars) from the sale of x cookies is given by
R(x) = 885 + 0.02x + 0.0003x2
Currently, the company sells 900 cookies per day.
Use marginal revenue to estimate the increase in revenue if the company increases sales by one cookie per day.
A) $92.00B) $0.56
C) $0.92
D) $56.00
13.
s(x) = -x2 - 20x - 19
A) Relative minimum at ( 20, -19)B) Relative maximum at ( -10, 81)
C) Relative maximum at ( 10, 81)
D) Relative maximum at ( -20, -19)
14.
f(x) = (-5x + 7)4
A) f '(x) = -20(-5x + 7)3B) f '(x) = -20(-5x + 7)4
C) f '(x) = -5(-5x + 7)3
D) f '(x) = 4(-5x + 7)3
15. A)
B)
C)
D)
16. A)
B)
C)
D)
17.
f(x) = 3 - 6x)140
A) f ' (x) = 4x; f ' (1) = 2B) f ' (x) = -840(3 - 6x)140
C) f ' (x) = 840(3 - 6x)139
D) f ' (x) = -840(3 - 6x)139
18.
Find the relative extrema of the function, if they exist.
f(x) = x2 - 4x + 7
A) Relative maximum at ( 3, 2)B) Relative maximum at ( 2, 3)
C) Relative minimum at ( 3, 2)
D) Relative minimum at ( 2, 3)
19.
Find the absolute maximum and absolute minimum values of the function, if they exist, over the indicated interval. When no interval is specified, use the real line (-?, ?).
f(x) = -21; [ -7, 7]
A) Absolute maximum: 21, absolute minimum: 0B) There are no absolute extrema.
C) Absolute maximum: 21, absolute minimum: -21
D) Absolute maximum: -21, absolute minimum: -21
20.
f(x) = -6x2 - 2x - 7
A) Relative maximum atB) Relative maximum at
C) Relative maximum at
D) Relative maximum at
Need Help can anyone help please A grocery store estimates that the weekly profit (in dollars) from the production and sale of x cases of soup is given by P(x) = -5600 + 9.5x - 0.0017x2 and currently 1300 cases are produced and sold per week. Use the marginal profit to estimate the increase in profit if the store produces and sells one additional case of soup per week. f(x) = e3x f(x) = 6x + 2; [-1, 2] f(x) = 2x2 - 16x + 27 f(x) = -3 - 7x; [-3, 1] Find the derivative of the function and evaluate the derivative at the given x-value. y = e7x/8. f(x) = 5x + 9 at x = 2 Differentiate. f(x) = (5x + 4)2 f(x) = 0.2x2 - 2.4x + 5.9 f(x) = x3 - 3x2 + 1 A company estimates that the daily revenue (in dollars) from the sale of x cookies is given by R(x) = 885 + 0.02x + 0.0003x2 Currently, the company sells 900 cookies per day. s(x) = -x2 - 20x - 19 f(x) = (-5x + 7)4 f(x)= -6e3x f(x) = 3 - 6x)140 Find the relative extrema of the function, if they exist. Find the absolute maximum and absolute minimum values of the function, if they exist, over the indicated interval. When no interval is specified, use the real line (-?, ?). f(x) = -6x2 - 2x - 7
Explanation / Answer
2) B
3)B
4) (b/2a) B
5) B
6) B
7) D
8) B
9) C
15)B
16)D
sorry ran out of time ill add the other answers
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.