A grinding wheel 0.25 m in diameter rotates at 2400 rpm. Calculate its angular v

Question

A grinding wheel 0.25 m in diameter rotates at 2400 rpm. Calculate its angular velocity in rad/s. Express your answer to two significant figures and include the appropriate units. What is the linear speed of a point on the edge of the grinding wheel? Express your answer to two significant figures and include the appropriate units. A grinding wheel 0.25 m in diameter rotates at 2400 rpm. What is the acceleration of a point on the edge of the grinding wheel? Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Given : diameter of the wheel - 0.25 m

rotations of the wheel = 2400 rpm

angular velocity = 2pi*N/60 = 2pi*2400/60 = 251.32 rad/s

b) linear speed = r*w = 0.125*251.32 = 31.41 m/s

c) a = v^2 / r = 31.41^2 / 0.125 = 7895.68 m/s2

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