A grinding wheel in the shape of a solid disk is 0.250m in diameter and has a ma

Question

A grinding wheel in the shape of a solid disk is 0.250m in diameter and has a mass of 2.50kg . The wheel is rotating at 2050rpm about an axis through its center.

Part A What is its kinetic energy? K=____J




Part B How far would it have to drop in free fall to acquire the same amount of kinetic energy? h=____m



Part A What is its kinetic energy? K=____J




Part A What is its kinetic energy? K=____J




K=____J



K=____J




Part B How far would it have to drop in free fall to acquire the same amount of kinetic energy? K=____J

Explanation / Answer

Part A)

The formula to apply is KEr = .5I2

I for a disk is .5mr2 = (.5)(2.5)(.125)2 = .01953 kg m2

= 2050 rev per min, which converts to 214.7 rad/s (2 rad per rev and 60 sec per min)

KEr = (.5)(.01953)(214.7)2

KEr = 450 J

Part B)

PE = mgh

450 = (2.5)(9.8)(h)

h = 18.4 m

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