1/x - 7dx = [ln |x - 7|] = ln(4) The answer should be equal to ln(11) There is n

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1/x - 7dx = [ln |x - 7|] = ln(4) The answer should be equal to ln(11) There is nothing wrong with the answer The integrand is not defined at x = 7 The integrand is not defined at x = 1 g(x) = (x2 + 1)2 (x - 1)5x3 4x/x2 + 1 - 5/x - 1 - 3/x (x2 + 1)2 (x - 1)5 x3 (4x/x2 + 1) + 5/x - 1 + 3/x) (x2 + 1)2 (x - 1)5 x3 (4x/x2 + 1) - 5/x - 1 - 3/x) 4x/x2 + 1 + 5/x - 1 + 3/x (x2 + 1)2 (x - 1)5 x3 (2x/x2 + 1) + 5/x - 1 + 3/x) y = (ex4 + 2)2 y' = ex4 + 2)ex4/x y' = 8 (ex4 + 2)2 x3 ex4 y' = 2 (ex4 + 2)x3ex4 y' = 8 (ex4 + 2)2 x3 ex4 y' = 4 (ex4 + 2)x3ex4 d/dx ((cos(x))x2 +2) -(sin(x))x2 + 2(x ln (cos(x)) + (x2 + 2) sin(x)/cos (x)) -(cos(x))x2 + 2(x ln(cos(x)) - (x2 + 2) sin(x)) (sin(x))x2 + 2(2x ln (sin(x)) - (x2 + 2) cos(x)/sin(x)) (cos(x))x2 + 2(x ln(cos(x)) + (x2 + 2) sin(x))/cos(x)) (cos(x))x2 + 2(x ln(cos(x)) + (x2 + 2) sin(x))/cos(x)) 2-x dx - 8/ln(2) - 8/ln (3) 1/16 ln(2) 3/16 ln(3) 1/32 ln(2)

Explanation / Answer

1) option D

2) option B

3) option D

4) option E

5) option C

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