| Question 9 8 pts In a non-evolving population of wildflowers, there are 497 in
ID: 282689 • Letter: #
Question
| Question 9 8 pts In a non-evolving population of wildflowers, there are 497 individuals with serrated leaves and there are 480 individuals with smooth leaves. If the allele for serrated leaves is dominant to the allele for smooth leaves, what is the expected frequency of the serrated allele? Round your answer to the nearest tenth of a percent (ie. 10.7%). Do not include the "%" sign in the box. DQuestion 10 8 pts In a certain breeding population, it is known for certain that only 8.1% of the individuals are "true. breeding" for the dominant phenotype. What would be the predicted frequency of individuals that are true-breeding" for the recessive phenotype? Round your answer to the nearest tenth of a percent (i.e. 10.7%). Do not include the "%" sign in the box.Explanation / Answer
9. The answer is
Accroding to HW law,
(p+q) = (p+q)^2 = p^2+2pq+q^2 = 1.
p = dominant allele and q = recesseive allele.
The proportion of recessieve phenotype i.e. qq or q^2 = 480/977 = 0.49
q^2 = 0.49, so, q= sqrt (0.49) = 0.7.
As p+q = 1, p = 1-q => 1-0.7 = 0.3.
The expected frequency of serrated allele = 0.3 or 30
ACCORDING TO CHEGG GUIDELINES WE HAVE TO ANSWER ONE QUESTION AT A TIME. POST THE REST AS SPERATE QUESTIONS, THEN I CAN HELP YOU.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.