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1. A testing lab owns a hydraulic load frame which was purchased for $35,000 ear

ID: 2790929 • Letter: 1

Question

1. A testing lab owns a hydraulic load frame which was purchased for $35,000 early in the lab's fiscal year 4 years ago. The internal bookkeeper uses a sum of the year's digits depreciation method assuming a life of 12 years and zero salvage value. For tax purposes, it is being depreciated with a 25% Capital Cost Allowance. The lab's MARR is 10%. The fiscal year is the same as the calendar year. The existing frame has no value on the second hand market. The operating and maintenance costs for this frame have remained constant, and will main constant, at $6500.00 per year. There is a new load frame on the market which sells for $40,000.00 and its operating and maintenance costs are estimated to be $3,000 in the first year, increasing by 15% per year. This new frame does have a second hand value estimated to decline 50% from the original purchase price in the first year, a further decline by 10% per year after. ) What was the internal depreciation charge that was made last year? b) What will the Undepreciated Capital Cost of the load frame be at the end of this fiscal year?

Explanation / Answer

(a) Last Year depreciation i.e. Depreciation for 4th Year Sum of years = 1 + 2+3+4+5+6+7+8+9+10+11+12 = 78 Depreciation for 4th Year = Cost x (useful life - years for which depreciation already charged)/Sum of years digit =35000 x (12-3)/78 $      4,038.46 (b) UCC = Cost - Accumulated depreciation Accumulated depreciation - Year Beginning balance Depreciation UCC= Beginning - depreciation 1 Rs. 35,000.00 Rs. 8,750.00 Rs. 26,250.00 2 Rs. 26,250.00 Rs. 6,562.50 Rs. 19,687.50 3 Rs. 19,687.50 Rs. 4,921.88 Rs. 14,765.63 4 Rs. 14,765.63 Rs. 3,691.41 Rs. 11,074.22 5 Rs. 11,074.22 Rs. 2,768.55 Rs. 8,305.66 Or u can simply do this - Cost x (1- Rate)^Year 35000 x (0.75)^5 8305.66406 Please provide feedback.. Thanks in advance.. :-)