2.Use the figure to answer the corresponding quest emmia Kay Normal male 10 11 1
ID: 276083 • Letter: 2
Question
2.Use the figure to answer the corresponding quest emmia Kay Normal male 10 11 12 13 maling Based on the phenotypes of the third generation. second generation must be: 2. the genotype of the father in the A. homozygous for albinism. B. heterozygous for hair color C. heterozygous for albinism. D. X-linked E. dominant. The genotypes of the normal females in the second generation in the accompanying figure are: 3. A. B. C. D. E. homozygous for albinism. heterozygous for hair color. heterozygous for albinism. X-linked. unknown. The inheritance pattern demonstrated by the pedigree in the associated figure is: A. B. C. D. E. 4. autosomal recessive. autosomal dominant. X-linked recessive. X-linked dominant. unknown from these data.Explanation / Answer
2) The answer will be heterozygous for albinism (Option C).
Explanation: Albinism is recessive disorder, i.e., both the genes must be recessive in order to get the disease. As it is not X-linked, so both parents must be carrying the recessive gene to develop the disease in progeny. Now, from the question we see that 7 & 8 are both normal male & female respectively & 11 developed albinism. Therefore, each of them is heterozygous for albinism.
3) The answer will be heterozygous for albinism (Option C).
Explanation: From the previous question we already saw that 8 is a carrier for albinism. Now, 5 & 6 both are normal female, but their father developed albinism. So, they must get one copy of recessive gene from their father. Thus both of them are carrier for albinism.
4) The answer will be autosomal recessive (Option A).
Explanation: We already saw that in order to develop the disease two copies of genes require, i.e., one copy of gene is not enough to develop the disease. Further, the disease is not X-linked recessive or dominant because then 5, 6 or 7 will develop the disease (which is not in our case).
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