(within an exon) 4. A permanent change from AAA to ATC in a DNA nucleotide tripl
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(within an exon) 4. A permanent change from AAA to ATC in a DNA nucleotide triplet in the template strand would result in 5. A change in the non-template strand within an exon from TTG to CTT would result in 6. Geckos store their genetic information in double-stranded DNA. In a tissue sample, 22% adenine was found in the extracted DNA. What is the percent guanine in this sample ? Give answer rounded to the nearest integer 7. If the G content in an entire DNA molecule is 12%, what are the % contents of the other nucleotides ? Give answer rounded to the nearest integer Do not include any other spaces in your answer 8. Match the correct term or phrase from the drop down list that corresponds to each letter in the figure. Terms may be used> 1 time or TERMS: stop codon A site P site start codon E site not at all. refers to linear ned mRNA DNA RNA anticodon stop anticodon codon start codon start anticodon polypeptide amino acid uncharged tRNA charged tRNA small ribosomal subunit large ribosomal subunit snRNA nefers to efers to refers to refers to 9. Based on the figure in the previous question (matching problem), what stage of translation is about to begin?Explanation / Answer
4. The answer is Stop codon.
ATC codes for UAG in mRNA. As UAG doesnot codes for any amino acid, it is called stop codon and this mutation is called nonsense muation.
5. The answer is glutamate.
TTG codes for asp and CTT codes for glu. so, it is called as minsense mutation.
6. The answer is 28%.
In DS DNA, %A= %t and %G = %C or vice versa.
As the sample is 22% of A, which means the T = 22%.
So, As %A=%T + %G=%C = 100%,
%G=%C = 100 - %A+%T
%G=%C = 100-44 = 56.
As %G=%C = 56,
the %G = 56/2 = 28%.
7. The answer is %G = 12%, %C = 12%, %A = 38% and %T = 38%.
In DS DNA, %A= %t and %G = %C or vice versa.
As the sample is 12% of G, which means the C = 12%.
So, As %A=%T + %G=%C = 100%,
%A=%T = 100 - 24
%A=%T = 100-44 = 76.
As %A=%T = 76,
the %A or %T = 76/2 = 38%.
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