(the opening shot of a game in which the player strikes a ball with his pool cue

Question

(the opening shot of a game in which the player strikes a ball with his pool cue). With the rail removed, a ball can fly off the table. the distance the pool ball lands from the table indicates the intial speed of the ball. As the only participant with a physics background, they have placed you in charge of determing the speed of the players break shots. The top of the pool table is 2.80 ft from the floor. The placement of the tape is such that 0 feet aligns to the edge of the table. The winner of the competition wants to know if he has broken the world record of 32mph. his ball landed a distance of 17.00ft from the table edge.
Calculate his break shot speed.

____________mph
At what speed did his pool ball hit the ground?
____________mph


please work out showing steps so i can learn how you aquired the answer. thank you

Explanation / Answer

find out the time it takes for the ball to hit the ground.

dy = 1/2 at2

2.8 ft = 1/2 * 32ft/s2 * t2

solve for t, t = .4183 seconds

now we can solve for the velocity

17 ft = vt

17 ft = .4183 v

v = 40.63 ft/s

converting that to mph

40.63 * (3600s/hr) * (1 mile/5280ft) = 27.71 mph

speed at ground is 27.71 in the x direction

in the y direction its

vy = 32 ft/s2 * .4183s = 13.39 ft/s

40.632 + 13.392 = v2   v = 42.78 ft/s = 29.17 mph

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