1. You calculate a Ch-Square value of 10.02 for data with 3 degrees of freedom (
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Question
1. You calculate a Ch-Square value of 10.02 for data with 3 degrees of freedom (df). What statement(s) can you make with respect to your null hypothesis? [1 can reiect the nuti hupothasis and Assuw 2. What if you had 6 degrees of freedom (di) with the same Chi-Square value (10.02) as the 0.104PLD.25, since pis previous problem? What statement(s) can you make with respect to your null hypothesis? than or UJE:fail to reject the null onupothesis, and You cross a cranberry bean plant (yes, they ure real) heterozygous for black streaked seeds with one (1) that has read streaked seeds. The Fi generation produces 375 black streaked seeds and 325 red streaked seeds. Does this data support the null hypothesis? Explain using Chi-Square analysis. [41 bb:home Failt rejet nul hup cannato colue A sign :3So expected Black strexlcedDisooncc 15 . Black Bec 4. What i here were 3750 black strealed seeds and 3250 red streaked seeds in the Fi generation? Does this data support the null hypothesis? Explain using Chi-Square analysis. Black streaLod 35DO 3 suD expected A Signifiant di Reenue dokseki?Explanation / Answer
Q 1. Your value of chi square with 3 degree freedom is 10.02. Therefore P lies between 0.025 and 0.01. Since P is less than 0.01. You can reject the null hypothesis. A significant difference was exit.
Q.2. Your value of chi square with 6 degree freedom is 10.02. Therefore P lies between 0.5 and 0.1. it fails to reject the null hypothesis. A significance difference was exit.
Q.3. Calculation of chi square value is right. But range of null hypothesis value is wrong. Its between 0.5 to 0.1
Q.4 : last answer was right.
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