Q1) The genetic distance in cM for the tan gene is 4344/10832. (True or false) Q
ID: 254585 • Letter: Q
Question
Q1) The genetic distance in cM for the tan gene is 4344/10832. (True or false)
Q2) The ratio of recombinant asci for the grey gene is [1897-(105+105+140+104)]/1897. (True or false)
Grey color gene an color gene Phenotype TTGG GGTT BBCC CCBB CTGB (GBCT) CTBG (BGCT) TCGB (GBTC) TCBG (BGTC) BTGC (GCBT) GTGT GTBC (BCGT) BCGT (GTBC) BCBC BTCG (CGBT) GTCB (CBGT) GTTG (TGGT) BCCB (CBBC) BCTG (TGBC) TBGC (GCTB) CBGT (GTCB) CBBC (BCCB) TGGT (GTTG) TGBC (BCTG) TBCG (CGTB) CBCB CBTG (TGCB) TGCB (CBTG) TGTG PD, NPD ouT Genotvpe #rec. Spores #non rec. spores #rec. Spores #non rec. spores 840 840 1120 832 664 720 712 760 376 268 1120 832 332 NPD 140 NPD 360 356 380 90 356 752 268 184 376 268 268 188 592 188 188 296 212 188 296 g+t+ gt g+t+ gt 40 212 232 328 196 gtt+ gt gt gtt+ gtt gtt+ gt+ gt gt g+t+ gt+ g+t 232 656 196 232 328 196 196 272 272 128 224 4500 128 224 10676 128 224 4344 128 224 10832 Total 1897Explanation / Answer
1. True
cM = Recombinant spores / Total spores = 4344/10832
2. True
The map distances between the centromere and the gray and tan genes were calculated by dividing the number of recombinant ascospores by the total number of ascospores, then multiplying by 100.
= (Total - Non recombinant / Total) X 100 = ( Recombinant / Total) X 100
= [1897-(105+105+140+104)]/1897
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