My 2nd question is : individual IV-2 marries a heterozygous affected woman. If t

Question

My 2nd question is : individual IV-2 marries a heterozygous affected woman. If they have 3 children, what is the probability that they will have 1 affected daughter and 2 affected sons? Briefly explain your answer. Remember to include sex in your probability calcuaitons.

1. Use the pedigree below to answer the following questions. 2 3 1 2 3 45 6 78 9 10 11 12 13 14 15 IV 1 2 3 4 5 6 7 8 9 10 You suspect the disease to be an X-linked dominant disorder. What are the possible genotypes and phenotypes of offspring from individuals 111-14 and ill-15? Denote the gene as"A" and use a Punnett square to help explain your answer. (2 points) A.

Explanation / Answer

Inheritance will be - X-linked dominant.

!st of all it's a dominant allelic inheritance because in every generation the character is being showed up.

next step is to check whether X-liked or Autosomal, it is X-linked

because you observe here if the father is affected then all female offsprings are being affected. And when the mother is affected then both male and female offsprings are affected (because the X chromosome in male and female offsprings are inherited from mother).

Coming to your question: IV-2 (unaffected male - XY) marries a heterozygous affected woman (XAX)

draw a Punnett square

the genotypes of offspring in the bold letter are affected due to the X-linked dominant allele.

the probability of 1 affected daughter - 1/4

the probability of 2 affected sons - 1/4*1/4 = 1/16

so the probability that they will have 1 affected daughter and 2 affected sons = 1/4 * 1/16 = 1/64

X Y XA XAX XAY X XX XY

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