receive 2 points. I. Single Trait Crosses 1. The ability to curl the tongue is a

Question

receive 2 points. I. Single Trait Crosses 1. The ability to curl the tongue is a dominant trait. A. If a woman is homozygous for curling the tongue, will she have any children who cannot curl their tongue? B. John can't curl his tongue, but both of is the genotype for each person? his parents can. What 2. In summer squash, white fruit color is dominant over yellow color A. Ifa heterozygous white squash is self-fertilized, what will be the ratio of white to yellow fruit in the offspring? B. If a heterozygous white squash is crossed with a yellow squash, what will be the ratio of white to yellow in the offspring? 3. In garden peas, purple flowers are dominant over white flowers. Two plants with purple flowers are crossed. They produce 324 purple and 103 white plants. What can we conclude about the genotypes of each parent plant? 4. In humans, having freckles is dominant over no freckles, and having unattached earlobes is dominant over attached earlobes. A. If an individual is homozygous dominant for both traits, and is crossed with a homozygous recessive individual for both traits, what is the ratio of traits in their offspring? B. If an individual is heterozygous for both traits, and crossed with an individual who is homozygous recessive for both traits, what is the ratio of traits in their offspring? C. If two individuals who are heterozygous for both traits are crossed, what is the ratio of traits in their offspring? III. Incomplete Dominance 5. Yellow guinea pigs (homozygous) crossed with white ones (homozygous) produce cream-colored offspring. If two cream- colored guinea pigs are crossed, list the possible genotypes and

Explanation / Answer

Answer:

I.

1A). No, she cannot have the children who cannot curl their tongue.

1B). The genotype of each parent is heterozygous.

2A). White (3) : Yellow (1)

Explanation:

Yy x Yy ----P1

Y

y

Y

YY (white)

Yy (white)

y

Yy (white)

yy (yellow)

2B). White (1) : Yellow (1)

Explanation:

Yy x yy—P1

y

Y

Yy (white)-50%

y

yy (yellow)-50%

3). Both parents are heterozygous purple flowers.

Pp x Pp ---P1

P

p

P

PP (purple)

Pp (purple)

p

Pp (purple)

pp (white)

Purple : White = 3:1 = 324 : 103

II.

Freckles (F) ; No freckles (f)

Unattached earlobe (E) ; Attached earlobe(e)

4A).

FFEE x ffee—P1

    FfEe (freckle and unattached earlobe)—progeny

4B).

FfEe x ffee ---Testcross

Fe

FE

FfEe (freckle and unattached earlobe)

Fe

Ffee (freckle and attached earlobe)

fE

ffEe (no freckle and unattached earlobe)

fe

ffee (no freckle and attached earlobe)

1:1:1:1

4C). FfEe x FfEe

Ee x Ee = E_ (3/4) & ee (1/4)

Ff x Ff = F_ (3/4) & ff (1/4)

Freckle and unattached earlobe = F_E_ = ¾ * ¾ = 9/16

Freckle and attached earlobe = F_ee= ¾ * ¼ = 3/16

No freckle and unattached earlobe = ffE_ = ¼ * ¾ = 3/16

No freckle and attached earlobe = ffee = ¼ * ¼ = 1/16

III.

5).

YY (yellow) x yy (white)—Parents

                Yy (cream)-------F1

Yy x Yy -----Selfcross

Y

y

Y

YY (yellow)

Yy (crem)

y

Yy (cream)

yy (white)

Y

y

Y

YY (white)

Yy (white)

y

Yy (white)

yy (yellow)

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