A spring with a force constant k = 130 N/m is attached to the bottom of a large

Question

A spring with a force constant k = 130 N/m is attached to the bottom of a large beaker which is then filled with water (figure (a)). A block of pine wood with a mass of 3.90 kg and density of 630 kg/m^3 is connected to the spring and the block-spring system comes to equilibrium as shown in figure (b). Determine the elongation deltaL of the spring. How is the buoyant force related to the weight of the block of pine wood and force created by the spring? How is the buoyant force related to the weight of water displaced? cm

Explanation / Answer

spring constant k =130N/m

mass = 3.90kg

density = 630kg/m^3

Buuyancy Force = mg*(1 - (pwater/pwood))

= 3.9*9.81*(1- (1000/630)) = -22.47 N

F = k*dx

dx = 22.47/130

= 0.172 m = 17.2 cm

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