You have a 6.0-in diameter plastic cup of water filled to the brim, and an ident

Question

You have a 6.0-in diameter plastic cup of water filled to the brim, and an identical plastic cup of water containing one ice cube of volume 1.1 in^3. The water level in the glass of water with ice is also filled to the brim, but part of the ice floats above the water level. What fraction of the ice floats above the water? The mass of water in the cup filled entirely with water is M. Compared to M, what is the mass of the water in the cup with the single ice cube? Compared to M, what will be the mass of water in the cup with the ice cube after the ice cube completely melts? A very small, hole forms from 3 in. from the top of the cup. What is the speed of the water leaving the hole when the hole first forms? What is the speed of the water leaving the hole after the water level has decreased by 1 in. from its original level at the brim of the cup? Instead use the fundamental physics principle: Bernoulli's equation. To do so, assume that the speed of the water at the top of the water level is negligible. This is a reasonable assumption because the water level drops pretty slowly in the cup if the hole is small. What is the longest vertical straw you could possibly drink this water through? Assume the straw is placed in the cup so that the bottom of the straw touches the top of the water level.

Explanation / Answer

volume of water= (4/3) pi (3)^3=113.076 in^3

% of ice submerged = density of ice / density of water x 100 = 93.4%

% of float= 100 - 93.4 = 6.6%

b. if volume of ice cube = Vi

then entire volume = M/dw

volume of water =(M/dw - Vi)

mass of water = (M/dw-Vi) xdw

mass of ice= Vixdi

so total mass =  (M/dw-Vi) xdw +  Vixdi

mass

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