HELP please solve What is F_2iX. the x-component of the new net force on q_2? Wh

Question

HELP please solve

What is F_2iX. the x-component of the new net force on q_2? What is F_1,x, the x component of the new net force on q1? How would you change qi (keeping q2.q3 and q^ fixed) in order to make the net force on q2 equal to zero? Increase its magnitude and change its sign Decrease its magnitude and change its sign Increase its magnitude and keep its sign the same Decrease its magnitude and keep its sign the same There is no change you can make to q1 that will result in the fet force on q2 being equal to zero.

Explanation / Answer

for 3rd question :

force of q3 on q2 is - 9*10^9 * 3.4*3.8 *10^-12/ 0.097*0.097 = 12.36N....

its x component is 12.36*cos(60) = 6.18N

also for force of q4 on q2 is also same and is 12.36 N and its x component is 6.18 N

force of q1 on q2 is 9*10^9 * 7.4*3.4 *10^-12/ 0.097*0.097 = 24.07N and it is its x component.

so

net F2x = 24.07+6.18+6.18 = 36.43 N

for 4th:

force of q3 on q1 is 9*10^9 * 7.4*3.8 *10^-12/ 0.097*0.097 = 26.9N.... its x component is 26.9*cos(60) = 13.45N

force of q4 on q1 is 9*10^9 * 7.4*3.8 *10^-12/ 0.097*0.097 = 26.9N.... its x component is 26.9*cos(60) = 13.45N

force of q2 on q1 is -9*10^9 * 7.4*3.4 *10^-12/ 0.097*0.097 = -24.07N and it is its x component

so net F1x = 13.45+13.45 - 24.07 = 2.83 N in the negative x directoin

so F1x is -2.83N

for 5th:

the answer is option B

decrease its magnitude and change the sign

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