Name: Student ID No.:- 12. Select the lightest available W12 section to support
ID: 2312189 • Letter: N
Question
Name: Student ID No.:- 12. Select the lightest available W12 section to support the axial loads Po 220 k and Pt. 280k if KL 14 ft and F, 50 ksi. Check for limiting width/ thickness ratios for both flange and web according to uniform compression in flanges and webs of doubly symmetric I-shaped sections for noncompact sections from Table B4.1. Flanges: tLs0.561 (Note: in Table B4 . 1 , b is used instead and, thus, b=br/2) Webs: h (Note: h d-2k) - 1.49 ratios may be calculated or obtained from Table 1-1,Explanation / Answer
PD=220 Kips
PL=280 kips
design load = 1.2*220 + 1.6*280=712 kips
effective length =14 ft
the lightest W12 section that has capapcity greater than 712 kips for effective length of 14 ft is W12x72 that has a axial compression capapcity of 759 kips
bf=12.04 in
tf=0.67 in
bf/2*tf=12.04/(2*0.67)=8.985
0.56*sqrt(E/fy) = 0.56*sqrt(29000/50)=13.49
8.985<13.49
h=9.125 in
tw=0.43
h/tw=9.125/0.43=21.22
1.49*sqrt(E/fy)=1.49*sqrt(29000/50)=35.88
21.22 < 35.88
Therefore, section is compact
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.