A swimming pool (20ft x 20 ft x 5 ft) has a small leak out the bottom. Measureme
ID: 2311214 • Letter: A
Question
A swimming pool (20ft x 20 ft x 5 ft) has a small leak out the bottom. Measurements of rainfall, evaporation, and water level are taken daily for 10 days as given below. Estimate the average daily leakage out of the swimming pool in ft3/day. Assume the pool is 5 ft (60 inches) deep on day 1
Day Evap (in) Rain (in) Level (inches)
1 0.5 60 (initial)
2 0 1.0
3 0.5
4 0 3.7
5 0.5
6 0.5
7 0 2.0
8 0.5
9 0.5
10 0.5 52 (ending)
please do not let Shekhar answer my question he is bad and just copying answers not related to the question. thank you
Explanation / Answer
Day
Evaporation
(in)
Rainfall or Precipitation
(in)
Level
(inches)
1
0.5
60 (Initially)
2
0
1.0
3
0.5
4
0
3.7
5
0.5
6
0.5
7
0
2.0
8
0.5
9
0.5
10
0.5
52 (Ending)
Outflow is given by
O = P – E - S ……………………….(1)
Where
P = Total precipitation = 1.0 + 3.7 + 2.0
P = 6.7 inches
E = Evaporation = 0.5 + 0 + 0.5 + 0 + 0.5 + 0.5 + 0 + 0.5 + 0.5 + 0.5
E = 3.5 inches
S = Total change in storage = Final level - Initial level
S = 52 – 60 = - 8 inches
(Negative sign shows there is decrease in water level)
Putting all these value in equation (1)
O = 6.7 – 3.5 – (-8)
Total outflow or Leakage O = 11.2 inches = 11.2/12 = 0.93333 ft
Pool Cross section Area = 20 ft x 20 ft
A = 400 ft2
Hence total volume of water leakage out = 400 x 0.9333 = 373.33 ft3 (in 10 Days)
Therefore The Average Daily Leakage Out = 373.33 / 10 = 37.333 ft3/day (Answer)
Day
Evaporation
(in)
Rainfall or Precipitation
(in)
Level
(inches)
1
0.5
60 (Initially)
2
0
1.0
3
0.5
4
0
3.7
5
0.5
6
0.5
7
0
2.0
8
0.5
9
0.5
10
0.5
52 (Ending)
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